Problem: 0(1(2(1(x1)))) -> 1(2(1(1(0(1(2(0(1(2(x1)))))))))) 0(1(2(1(x1)))) -> 1(2(1(1(0(1(2(0(1(2(0(1(2(x1))))))))))))) 0(1(2(1(x1)))) -> 1(2(1(1(0(1(2(0(1(2(0(1(2(0(1(2(x1)))))))))))))))) 0(1(2(1(x1)))) -> 1(2(1(1(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(x1))))))))))))))))))) 0(1(2(1(x1)))) -> 1(2(1(1(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(x1)))))))))))))))))))))) 0(1(2(1(x1)))) -> 1(2(1(1(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(x1))))))))))))))))))))))))) 0(1(2(1(x1)))) -> 1(2(1(1(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(x1)))))))))))))))))))))))))))) 0(1(2(1(x1)))) -> 1(2(1(1(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(x1))))))))))))))))))))))))))))))) 0(1(2(1(x1)))) -> 1(2(1(1(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(x1)))))))))))))))))))))))))))))))))) 0(1(2(1(x1)))) -> 1(2(1(1(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(x1))))))))))))))))))))))))))))))))))))) 0(1(2(1(x1)))) -> 1(2(1(1(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(x1)))))))))))))))))))))))))))))))))))))))) 0(1(2(1(x1)))) -> 1(2(1(1(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(x1))))))))))))))))))))))))))))))))))))))))))) Proof: Bounds Processor: bound: 2 enrichment: match automaton: final states: {3} transitions: 11(22) -> 23* 11(24) -> 25* 11(19) -> 20* 11(21) -> 22* 11(16) -> 17* 21(15) -> 16* 21(32) -> 33* 21(26) -> 27* 21(23) -> 24* 21(18) -> 19* 01(20) -> 21* 01(17) -> 18* 12(52) -> 53* 12(54) -> 55* 12(49) -> 50* 12(51) -> 52* 12(46) -> 47* 00(2) -> 3* 00(1) -> 3* 22(60) -> 61* 22(45) -> 46* 22(58) -> 59* 22(53) -> 54* 22(48) -> 49* 10(2) -> 1* 10(1) -> 1* 02(50) -> 51* 02(47) -> 48* 20(2) -> 2* 20(1) -> 2* 1 -> 26* 2 -> 15* 21 -> 32* 24 -> 45* 25 -> 18,3 27 -> 16* 33 -> 19* 51 -> 58* 54 -> 60* 55 -> 21,32 59 -> 49* 61 -> 46* problem: Qed